(1/2)10t^2+20t=480

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Solution for (1/2)10t^2+20t=480 equation: 



(1/2)10t^2+20t=480

We move all terms to the left:

(1/2)10t^2+20t-(480)=0



Domain of the equation: 2)10t^2!=0

t!=0/1

t!=0

t∈R



We add all the numbers together, and all the variables

(+1/2)10t^2+20t-480=0

We add all the numbers together, and all the variables

20t+(+1/2)10t^2-480=0

We multiply all the terms by the denominator


20t*2)10t^2+(-480*2)10t^2+1=0

We add all the numbers together, and all the variables

20t*2)10t^2+(-960)10t^2+1=0

Wy multiply elements

40t^2-960)10t^2+1=0

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